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3 years ago

A cone has a volume of 6782.4 cubic centimeters and a radius of 18 centimeters. What is its height?

Mathematics

1 answer:

ELEN [110]3 years ago

4 0

Answer: 19.99cm

Step-by-step explanation: trust

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Which equation represents this statement?

Furkat [3]

Answer:

The correct equation is 23n=65

Step-by-step explanation:

23n=65 means a number 'n' multiplied with 23 gives you the product 65.

7 0

2 years ago

About how many students do not prefer non- fiction?

slamgirl [31]

Answer:

B. 75%

Step-by-step explanation:

If about a quarter ( 25% ) do like non-fiction, then we know that the rest do not prefer it ( 75% )

75 + 25 = 100

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2 years ago

PLEASE ANSWER ASAP, WILL GIVE BRAINLIEST IF CORRECT

emmasim [6.3K]

If x > 0 then |x|/x = 1 !!!

If x<0 then |x|/x = -1

*below is an explanation! :)

_______________________________________

- I found the answer to this by choosing a any number that satisfies the requirement of x > 0 and plugging it into |x|/x

-----

Watch this!

Let's take 10 for example. 10 is greater than 0 like x>0 requires!

Let's plug it into |x|/x

|10| ÷ 10 = 1

*Remember that | | this means "absolute value" or whatever is in between the two bars will always be positive (+)

-------

Now let's take a random number that satisfies 0> x and do the same as we did above!

Let's take -3 and plut it into |x|/x

|-3| ÷ -3 = -1

8 0

2 years ago

Read 2 more answers

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

Marina86 [1]

Area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

$$=\frac{1}{4} \pi r^2 - \frac{1}{2} bh$

$$=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times 12 \times 12$

$$=36\pi -72$

$$=36(\pi -2)$ square cm.

Area of the shaded region $$=36(\pi -2)$ square cm

Using Pythagoras theorem,

$AC^2=AB^2+BC^2$

$AC^2=12^2+12^2$

$AC^2=288$

Taking square root on both sides of the equation, we get

$AC= 12\sqrt 2$ cm

Perimeter of the quadrant of a circle = $\frac{1}{4} \times 2\pi r$

$$=\frac{1}{4} \times 2 \times \pi \times 12$

$$=6 \pi$ cm

Perimeter of the shaded region = $6 \pi + 12\sqrt 2$ cm

$=6 (\pi + 2\sqrt 2)$ cm

Hence area of the shaded region $$=36(\pi -2)$ square cm

Perimeter of the shaded region $=6 (\pi + 2\sqrt 2)$ cm

6 0

3 years ago

Amber has 3/4 Ib. of strawberry icing. She needs 1/8 of a Ib. of strawberry icing for each cake she makes. How many cakes can sh

Svetach [21]

Amber can make 6 cakes

4 0

3 years ago