Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
方法/步骤
右键单击以选择此计算机，然后有一个菜单来选择属性。
选择后，打开属性面板以找到我们的高级系统设置。
打开后，我们在系统设置下找到高级设置。
打开后，我们看到下面有一个环境变量选项。
打开后，我们在右下角看到一个删除选项。
单击删除到，在右下角后单击删除，然后单击确定的选项。 ...
本文未经授权摘自百度经验
Answer:
interface GUIComponent{
public void open();
public boolean close();
public void resize(int width, int height);
public void move(int x, int y);
}
Explanation:
