The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
brainly.com/question/14391067
#SPJ1
You could just put 0 for a and b.
It would work.
To find x, we have to use the pythagorean theorem.
a^2 + b^2 = c^2.
In our problem,
a = 3
b = ?
c = 6.5
(3)^2 + b^2 = (6.5)^2
Simplify the left and right side.
9 + b^2 = 42.25.
Subtract 9 from each side
b^2 = 33.25.
Take the square root of each side
b = 5.8.
Multiply 5.8 by two becuase 5.8 is the radius and we are looking for the diameter
x = 11.6
<span>–11 – (–15)
Subtract -15 from -11. *Note: If a negative number is being subtracted from another number, it automatically make an addition sign. And so -11-(-15) would be the same as -11 + 15 or the same as 15 - 11.
Final Answer: C. 4
</span>
Answer:
Apologies if I am incorrect.