The solution to given system of equations is x = 2 and y = -5
<em><u>Solution:</u></em>
<em><u>Given the system of equations are:</u></em>
4x + y = 3 ---------- eqn 1
-2x + 3y = -19 ---------- eqn 2
We have to find the solution to above system of equations
<em><u>We can solve the system by substitution method</u></em>
From eqn 1,
4x + y = 3
Isolate y to one side
y = 3 - 4x ----------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
-2x + 3(3 - 4x) = -19
-2x + 9 - 12x = -19
Combine the like terms
-14x = -19 - 9
-14x = -28
Divide both sides of equation by -14
<h3>x = 2</h3>
<em><u>Substitute x = 2 in eqn 3</u></em>
y = 3 - 4(2)
y = 3 - 8
<h3>y = -5</h3>
Thus the solution is x = 2 and y = -5
Answer:
it is 2xy^2z^3 if the number under the square root(5)√(32x^(5)y^(10)z^(15))
Step-by-step explanation:
C should be your answer:))))
Problem 16
Divide both sides by 2 to undo the multiplication of 2 (done to the t).
2t > 324
2t/2 > 324/2
t > 162
Answer: t > 162
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Problem 17
Similar to problem 16, we will divide both sides by 12
12y >= 1
12y/12 >= 1/12
y >= 1/12
Answer: y >= 1/12
Note: the symbol ">=" without quotes means "greater than or equal to".
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Problem 18
To undo the division of 9.5, we multiply both sides by 9.5
x/9.5 < 11
9.5*x/9.5 < 9.5*11
x < 104.5
Answer: x < 104.5
