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horrorfan [7]
3 years ago
9

Four less than the sum of a number and 20 is 16. What is the number

Mathematics
1 answer:
Allushta [10]3 years ago
3 0
[tex]4 - (x + 20 ) = 16

x=0
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Solve 3x − 5y = 17<br> 9x − 15y = −4
dangina [55]

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55

Step-by-step explanation:

8 0
3 years ago
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What is the sum of ​​​​​​12,837.45 and 15,910.65? Enter your answer in the box below.
Minchanka [31]

Answer: 28748.1

Step-by-step explanation:

6 0
3 years ago
$120; Markup: 35%<br><br>What's the final price? pls show how u got the answer...​
Tju [1.3M]

Answer: 162

Step-by-step explanation:

So you will need to find the Markup. The original cost is $120.

  1. Divide the number by 100 is 1.2. $1.2 is 1% of the $120.
  2. Now times the number by 35. $1.2 x 35 is $42.
  3. Finally, add the number. 120 + 42 = 162.

I hope this is the answer you are looking for.

4 0
3 years ago
One year Roger had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male p
baherus [9]

Answer:

(a) The <em>z</em>-score of Roger is -1.56 and the <em>z</em>-score of Amber is -1.13.

(b) Roger had a better year relative to his peers.

Step-by-step explanation:

If X follows N (<em>µ, σ</em>₂), then z=\frac{x-\mu}{\sigma}, is a standard normal variate with mean,      E (Z) = 0 and Var (Z) = 1. That is, Z follows N (0, 1).

Let <em>X</em> = ERA of male pitchers and <em>Y</em> = ERA of ERA of female pitchers.

It is provided that the mean and standard deviation of <em>X</em> are:

\mu_{X}=4.371\\\sigma_{X}=0.787

Also, the mean and standard deviation of <em>Y</em> are:

\mu_{Y}=4.363\\\sigma_{Y}=0.869

ER of Roger is 3.14 and ERA of Amber is 3.38.

(1)

Compute the <em>z</em>-score of Roger as follows:

z=\frac{x-\mu_{X}}{\sigma_{X}}=\frac{3.14-4.371}{0.787}=-1.56

Thus, the <em>z</em>-score of Roger is -1.56.

Compute the <em>z</em>-score of Amber as follows:

z=\frac{x-\mu_{Y}}{\sigma_{Y}}=\frac{3.38-4.363}{0.869}=-1.13

Thus, the <em>z</em>-score of Amber is -1.13.

(2)

Compute the probability of ERA's that are greater than Roger's ERA as follows:

P(X>3.14)=P(\frac{X-\mu}{\sigma}>\frac{3.14-4.371}{0.787})\\=P(Z>-1.56)\\=P(Z

This implies that 94% of the other male pitchers had an ERA higher than 3.14.

Compute the probability of ERA's that are greater than Amber's ERA as follows:

P(Y>3.38)=P(\frac{Y-\mu_{Y}}{\sigma_{Y}}>\frac{3.38-4.363}{0.869})\\=P(Z>-1.13)\\=P(Z

This implies that 87% of the other female pitchers had an ERA higher than 3.38.

As it is provided that the lower the ERA the better the pitcher, then it can be concluded that Roger had a better year relative to his peers.

4 0
4 years ago
Dan went to the mall on saturday to buy clothes . He paid $8.49 on shorts and $5.82 on a jacket with a $20 dollar bill. How much
natka813 [3]

Answer:

he paied 14 dollars and 31 cents

Step-by-step explanation:

If i read it right you just add 8.49 and 5.82

6 0
3 years ago
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