Given (-4,9) (-8,9),(-9,7,(-9,4)
...
To Find : plot the point and draw quadrilateral
Solution:
(-4,9)
go 4 left of origin and then go 9 up
(-8,9)
go 8 left of origin and then go 8 up
(-9,7)
go 9 left of origin and then go 7 up
(-9,4)
go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up
join (-9,7) with (-8,9) and (-9,4)
Quadrilateral is constructed
Answer:
The answer is 030
Step-by-step explanation:
I am unable to transmit my working but don't forget to write the bearing as 030 not 30
Answer:
but what is the value of term 'n'
Step-by-step explanation:
n=3
2n-1
2×3-1
6-1
5
Ans
Answer:
119 maybe, not completely sure
Step-by-step explanation:
I think 119
<h3>
Answers: x = -17 and x = 64</h3>
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Explanation
Consider three scenarios:
- A) The value of x is the smallest of the set (aka the min)
- B) The value of x is the largest of the set (aka the max)
- C) The value of x is neither the min, nor the max. So 8 < x < 39.
These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.
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We'll start with scenario A.
If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}
The range is 56, so,
range = max - min
56 = 39 - x
56+x= 39
x = 39-56
x = -17 which is one possible answer
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If instead we go with scenario B, then x is the max and 8 is the min
range = max - min
56 = x - 8
56+8 = x
64 = x
x = 64 is the other possible answer
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Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.
Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.
