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Levart [38]
3 years ago
7

Donald operates an accounting firm and has an annual summer party for the employees and their families. He believes the party be

nefits his employees. The cost of the food and beverages served at the party is $5,500. Donald also pays a band $500 to play at the party. How much of the total cost can Donald deduct?
Business
2 answers:
user100 [1]3 years ago
7 0

Answer:

$6,000

Explanation:

Total cost includes all that was expended on the party. This includes the cost of the food and the band.

Total cost = $5,500 + $500 = $6,000

I hope my answer helps you

Vsevolod [243]3 years ago
5 0

Answer:

$6000

Explanation:

Accordingly, the costs associated with throwing a party for employees and their families (spouses and significant others) are fully deductible (100%) as long as the party is hosted primarily for the employees. In this case, the party is for the employees as it is seen to benefits them, thus, total cost Donald can deduct equals cost of beverages and food plus cost of band,

That is,

= 5500 + 500

=$6000

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Answer:

Consumer behavior

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3 0
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The following data was collected from the manufacturing of an auto component. It represents the diameter (in mm) of that compone
andre [41]

Answer:

9.37

Explanation:

The computation of LCL for a control chart is shown below:-

Sample  Obs 1  Obs 2    Obs 3   Obs 4   Mean observation    Range

1                 10      12           12          14              12                         4

2                 12     11            13          16              13                          5

3                 11      13            14           14              13                          3

4                 11       10            7            8               9                          4

5                13     12             14            13             13                         2

For computing the mean observation  and range we will use the below formulas

Mean observation = ( Obs 1 + Obs 2 + Obs 3 + Obs 4) ÷ 4

Range = Highest value - Lowest value

LCL =  \bar{\bar{X}} - A2 \bar{R}

\bar X =  ( 12 + 13 + 13 + 9 + 13 ) ÷ 5

= 12

\bar R =  ( 4 + 5 + 3 + 4 + 2 ) ÷ 5

= 3.6

Since we found the value of A2 with the help of constants table for control charts for a 4 subgroup size.

A2  = 0.729

LCL =  \bar{\bar{X}} - A2 \bar{R}

12 - 0.729 × 3.6

= 9.37

5 0
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Answer:

true

Explanation:

6 0
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