Question

What is the smallest possible integer value of $x$ if $12\div(x+1)$ is an integer?

Answer 1

Answer:

The answer is -13.

Step-by-step explanation:

We get the smallest value of $x$ when $x+1$ is the most negative factor of 12, which is -12. Therefore,

                                                     $x+1=-12\\x=\boxed{-13}$