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qaws [65]
3 years ago
5

What is the smallest possible integer value of $x$ if $12\div(x+1)$ is an integer?

Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

The answer is -13.

Step-by-step explanation:

We get the smallest value of x when x+1 is the most negative factor of 12, which is -12. Therefore,

                                                     x+1=-12\\x=\boxed{-13}

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