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ehidna [41]
4 years ago
7

You performed an experiment to find out how strong the net below a trapeze should be to safely catch a performer of mass 80 kg.

Which of the following is a new scientific question that can be investigated in the laboratory?
A. It is more exciting to watch a trapeze artist without a net?
B. How long can you use the net before it breaks?
C. Is trapeze more or less exciting to watch than gymnastics?
D. Should trapeze artists wear red or blue outfits?
Physics
2 answers:
Mrac [35]4 years ago
6 0

    They tell you what the scientists are looking for in the experiment, "find out how strong the net below a trapeze should be". Using that you find out that the only question that questions the strength of the net is B.  

Nostrana [21]4 years ago
3 0
The answer would be b
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A wave has a frequency of 1000 Hz. If the wavelength is 0.5 m, how fast is the wave<br> traveling?
Soloha48 [4]

Answer: 1000 Hz · 0,5 m = 500 m/s

Explanation: speed = frequency · wavelength

7 0
3 years ago
The half-wave rectifier circuit of vs(t) = 170 sin(377t) V and a load resistance R = 15Ω. Determine: a. The average load current
irina1246 [14]

Answer:

a  average load current = 11.33 A

b rms load current = 8.02A

c true power =962.64 W

d apparent power =962.64 W

e. power factor cosθ =1

Explanation:

Vs (t) = 170 sin(377t) v

Vm =170v

Vrms = 170/√2 =120.23 v

Im = Vm/R = 170/15 = 11.33 A

Irms = Im/ √2 = 11.33/√2 =8.02A

Resistors are electronic components that consume energy

the power in a resistor is given by  P =IVcosθ ; in a resistor cosθ =1

P =IV

The electrical power consumed by a resistance, (R) is called the true or real power

and is obtained by multiplying the rms voltage with the rms current.

P= Vrms × Irms

120.03×8.02

P= 962.64 W ; true power

apparent power = Vrms × Irms

=120.03×8.02

= 962.64W ; apparent power

power factor cosθ = true power/ apparent power

cosθ = 962.64/962.64

cosθ = 1

For the purely resistive circuit, the power factor is 1 , because the reactive power is equal to zero (0).

6 0
3 years ago
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A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un
KonstantinChe [14]

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

x=vt=23.3\frac{m}{s}t

and the police car distance:

x=vt+\frac{at^{2}}{2}=0+\frac{2.75\frac{m}{s^{2}} t^{2}}{2}=0.73\frac{m}{s^{2}}

Since they both travel the same distance x, we can equal both formulas and solve for t:

0 = 0.73\frac{m}{s^{2}}t^{2}-23.3\frac{m}{s} t\\\\0=t(0.73\frac{m}{s^{2}}t-23.3\frac{m}{s} )\\\\

Two solutions exist to the equation; the first one being t=0

The second solution will be:

0.73\frac{m}{s^{2}}t=23.3\frac{m}{s}\\\\t=\frac{23.3\frac{m}{s}}{0.73\frac{m}{s^{2}}}=32s

This result allows us to confirm that the police car will take 32s to catch up to the speeder

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3 years ago
What is the angle of deviation in a plane mirror at normal incidence?​
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Answer:

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Answer:

B. GRAVITY is the answer

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