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3 years ago

7

You performed an experiment to find out how strong the net below a trapeze should be to safely catch a performer of mass 80 kg.

Which of the following is a new scientific question that can be investigated in the laboratory?
A. It is more exciting to watch a trapeze artist without a net?
B. How long can you use the net before it breaks?
C. Is trapeze more or less exciting to watch than gymnastics?
D. Should trapeze artists wear red or blue outfits?

2 answers:

Mrac [35]3 years ago

6 0

They tell you what the scientists are looking for in the experiment, "find out how strong the net below a trapeze should be". Using that you find out that the only question that questions the strength of the net is B.

Nostrana [21]3 years ago

3 0

The answer would be b

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Which of the following is an example of a conductor?

nordsb [41]

Answer: B. a gold chain

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A car accelerates at a constant rate from 0 to 50 mph in three fourths min. How far does the car travel during that time?

Helen [10]

Answer:

the car have travelled 0.31 mile during that time

Explanation:

Applying the Equation of motion;

s = 0.5(u+v)t

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s = distance travelled

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Substituting the given values into the equation;

s = 0.5(0+50)×(1/80)

s = 0.3125 miles

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2 years ago

A plate drops onto a smooth floor and shatters into three pieces of equal mass.Two of the pieces go off with equal speeds v at r

Firlakuza [10]

Answer:

Speed of the this part is given as

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As we know by the momentum conservation of the system

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here we know that

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so we will have

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now from above equation we have

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2 years ago

A yellow and green car traveled 400 miles to Dayton, OH. The green car made the trip in 10 hours. The yellow arrived in 8 hours.

elixir [45]

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The speed of each car is defined as:

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For the green car, d=400 mi and t=10 h, so its speed is

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So, the correct choice is

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4 0

3 years ago

Read 2 more answers

The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on

alekssr [168]

Answer:

The change in temperature is $\Delta T = 1795 K$

Explanation:

From the question we are told that

The temperature coefficient is $\alpha = 4 * 10^{-3 }\ k^{-1 }$

The resistance of the filament is mathematically represented as

$R = R_o [1 + \alpha \Delta T]$

Where $R_o$ is the initial resistance

Making the change in temperature the subject of the formula

$\Delta T = \frac{1}{\alpha } [\frac{R}{R_o} - 1 ]$

Now from ohm law

$I = \frac{V}{R}$

This implies that current varies inversely with current so

$\frac{R}{R_o} = \frac{I_o}{I}$

Substituting this we have

$\Delta T = \frac{1}{\alpha } [\frac{I_o}{I} - 1 ]$

From the question we are told that

$I = \frac{I_o}{8}$

Substituting this we have

$\Delta T = \frac{1}{\alpha } [\frac{I_o}{\frac{I_o}{8} } - 1 ]$

=> $\Delta T = \frac{1}{3.9 * 10^{-3}} (8 -1 )$

$\Delta T = 1795 K$

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3 years ago