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ankoles [38]
3 years ago
11

How much work is done by a crane that lowers 1000N of material a distance of 150

Physics
2 answers:
ludmilkaskok [199]3 years ago
3 0
The crane does NO work.

Work = (force) x (distance)

         = (1,000 N) x (150 meters ?)  =  150,000 joules

But the work is in the direction of the force, and it isn't the crane
pushing the material down.  It's gravity.

Gravity is doing the work. 

If the material was being lowered by a cable wrapped around the shaft
of an electric generator, then you could use the work done by gravity to
generate some electrical energy, and then sell the energy.

Or, if the "material" happened to be water, you could let gravity lower it
through a turbine or a water wheel, and use the work done by gravity to
grind wheat.

Yes, the crane may be raising a sweat, working against gravity.  The
purpose is only to prevent gravity from doing the work too fast.
Citrus2011 [14]3 years ago
3 0
Since workdone is Force times distance Given force-1000n Distance-150 Wd-1000 times 150 Wd-150000n.
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Think about a typical school day. In the space provided below, describe how each of the different forms of energy we have learne
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3 0
2 years ago
Read 2 more answers
Which law of motion accounts for the following statement?
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I know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...
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3 years ago
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A 5 kg ball rolling at 1.0 m/s hits a 15 kg ball at rest. The balls stick together after the collision What is the
Reika [66]

Answer:

0.25m/s

Explanation:

Given parameters

m₁  = 5kg

v₁ = 1.0m/s

m₂ = 15kg

v₂ = 0m/s

Unknown:

velocity after collision = ?

Solution:

Momentum before collision and after collision will be the same. For inelastic collision;

    m₁v₁ + m₂v₂  = v(m₁ + m₂)

Insert parameters and solve for v;

   5 x 1  + 15 x 0 = v (5 + 15 )

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5 0
3 years ago
Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam
sasho [114]
Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around
3 0
3 years ago
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