Answer:
B) below the plane and behind it.
Answer:
a)= 29.4J
b)F = 588 N
c)= 60 Kg
Explanation:
Force constant of the spring (k) = 5880 N/m
Change in length of the spring (x) = 25 - 15 = 10 cm 0.1m
This work done on the spring as it is stretched (or compressed) can be recovered. This is stored work that can be used to do work on something else by this spring. That means the stretched (or compressed) spring has energy -- potential energy. This is spring potential energy or elastic potential energy.
a) Work done in pulling the body W = 1/2kx²
= 1/2 (5880)(0.1)2
= 29.4J
b)From Hook's Law,
F = ke
Where F = applied force, k = spring constant, e = extension.
Given: k = 5880 N/m, e = 25-15 = 10 cm = 0.1 m.
Substitute into the formula above
F = 5880(0.1)
F = 588 N
c)By using the formula, F = -kx
Hence mg = kx
Thus m x 9.8 =5880 x0.1
Hence mass of the body
m= 5880 x0.1/9.8
= 60 Kg
Answer:
m = 0.217 kg
Explanation:
We can solve this exercise using the conservation of angular momentum. For this the system is formed by the bar and the disk, so that the forces during the crash have been internal and the angular momentum is preserved
initial angular mount. Before impact
L₀ = L_bar + L_ disk
L₀ = I_bar w₀ + m r v₀
final angular momentum. Right after the crash
= I_bar wf = m r v_{f}
The moment of inertia of a bar that rotates at its ends is
I_bar = 1/12 M L
how the angular momentum is conserved
L₀ = L_{f}
I_barr w₀ + mr v₀ = I_barr w_{f} + m r v_{f}
I_bar (w₀- w_{f}) = m r (v₀- v_{f})) r
m = I_bar (w₀ - w_{f}) / r (v₀ -v_{f})
m = 1/12 M L (w₀ -w_{f} ) / r (v₀ -v_{f})
in the exercise it indicates that the initial speed of the disc is v₀ = 20 m / s and its final speed is v_{f} = -16 m / s, the negative sign is because the disc recoils
we calculate
m = 1/12 35 0.90 (0 + 1.14) / [0.30 (30- (-16))]
m = 0.217 kg
Answer:
D. Left
Explanation:
The question is worded weirdly, but based on the fact that heat transfers from hot to cold and the temperature on the right is warmer than the temperature on the left, I would say that the heat is flowing from the box on the right to the box on the left.
I hope this makes sense and was helpful! ☺
Answer:
= 2,018.3 J
Explanation:
mass (m) = 1.1 kg
velocity (v) = 62 m/s
initial angle(θ) = 12.3°
kinetic energy = ![0.5mv^{2}](https://tex.z-dn.net/?f=0.5mv%5E%7B2%7D)
where
- m is the mass
- v is the velocity, which has two components
v = Vx + Vy (horizontal component + vertical component)
at the maximum height, velocity is 0, so Vy = 0 and v= Vx
v = Vx = v.cosθ
v = 62 x cos 12.3 = 60.6 m/s
therefore kinetic energy =
= ![0.5x1.1x60.6^{2}](https://tex.z-dn.net/?f=0.5x1.1x60.6%5E%7B2%7D)
= 2,018.3 J