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lozanna [386]
3 years ago
14

Please explain the process and equation to get the answer

Physics
1 answer:
Juliette [100K]3 years ago
8 0

The shell's horizontal position x and vertical position y are given by

x=v_0\cos55.0^\circ\,t

y=v_0\sin55.0^\circ\,t-\dfrac g2t^2

where v_0 is the given speed of 1.70 x 10^4 m/s, and g is the acceleration due to gravity (taken here to be 9.80 m/s^2).

To find the horizontal range, you can use the range formula,

x_{\rm max}=\dfrac{{v_0}^2\sin2\theta}g

with \theta being the angle at which the shell is fired.

Alternatively, we can work backwards and deal with part (b) first:

(b) The time spent in the air is the time it takes for the shell to reach the ground. To find that, you solve for t in y=0:

v_0\sin55.0^\circ\,t-\dfrac g2t^2=0\implies t\approx284\,\rm s

(a) After this time, the shell will have traveled horizontally

x=v_0\cos55.0^\circ(284\,\rm s)\approx2.77\times10^5\,\rm m

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