◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer:
use mmaatthh wwaayy
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
If x was equal to 12, 22.5 or 10 the side would be too large compared to 15. This is only correct if the drawing is to scale, however.
In one year, $ 9,000 with a profit of 7.75%, is $ 697.5
697.5 × 18 = 12555
After 18 years old, it is $ 15,222
Answer:
2730
Step-by-step explanation:
We want to determine the greatest common divisor of the elements of the set 
We apply the Fermat's little theorem which states that if p is a prime number, then for any integer a, the number aᵖ − a is an integer multiple of p.
Now, 
if p-1 divides 12.
Since the of 12 are 1,2,3,4, 6, 12, the corresponding primes are 2, 3, 5, 7, 13.
Therefore, the gcd of the elements in 
and 
2*3*5*7*13=2730
Therefore, the gcd of the elements in set S is 2730.
