Answer:
The answer to your question is:
x = 1
y = 1
z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (1)
-2x - y + z = -3 (2)
2x + 3y + 3z = 5 (3)
Solve (1) and (2)
Multiply 2 by 2
-2x + 2y + 3z = 0
-4x -2y + 2z = -6
-6x + 5 z = -6 (4)
Solve (2) and (3)
Multiply 2 by 3
-6x - 3y + 3z = -9
2x + 3y + 3z = 5
-4x + 6z = -4 (5)
Solve (4) and (5)
Multiply (4) by 2 and (5) by -3
-12x + 10 z = -12
12x - 18z = 12
-6z = 0
z = 0
Then
-4x + 6(0) = -4
-4x = -4
x = -4/-4
x = 1
Finally
-2(1) - y + (0) = -3
-2 - y = -3
-y = -3 + 2
y = 1
N/2 -7 = -6
add 7 to both sides;
n/2 -7+7 = -6+7
n/2 = 1
multiply both sides by 2 ( or divide by 1/2 ) in order to get n by itself.
n/2 * 2/1 = 1 * 2/1
n = 2
Answer:
7776
Step-by-step explanation:
Yes.
Hello
<span>y= e^x (x^2 -7x +13)
y' = (</span>e^x)' (x^2 -7x +13)+e^x (x^2 -7x +13)'
y' = e^x(x^2 -7x +13)+e^x (2x-7)
y" = e^x(x^2 -7x +13)+e^x (2)
y"=e^x(x^2 -7x +15)
