And? It’s there a full question?
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
14/5-5/6=84/30-25/30=59/30
59/30=1 and 29/30
To answer the problem just add the frequencies that
correspond to email counts that are 19 or fewer. So you're adding the counts
that correspond to 0-9 and 10-19. So the frequency of 0-9 is 4 and the
frequency of 10 -19 is 7. So 4 + 7 = 11
The probability of an event can help make predictions by knowing the chance of something happening and using your knowledge to determine the probability of choosing for example blue on a spinner out of 6 with 4 blues. there is 4 blues and 2 red so you predict it will be on red because there is more of it
