Radial symmetry I believe
Answer:
1. gravitational potential energy to kinetic energy
2. chemical energy to mechanical energy
Added a picture for proof :) I just took the test
<h3><u>Answer;</u></h3>
In metaphase I, the chromosome tetrads align on metaphase plate
while in metaphase II, chromosomes align on metaphase plate as they are in mitosis with only sister chromatids.
<h3><u>Explanation;</u></h3>
- Meiosis is a form of cell division that halves number of chromosomes when forming specialized reproductive cells such as gametes
.
- Meiosis occurs in two phases, namely; meiosis I and meiosis II. During homologous pairs of chromosomes align on the equatorial plane at the center of the cell.
- During metaphase II, the spindle fibers connect to the kinetochore of each sister chromatid. The chromosomes align at the equatorial plane, which is rotated 90° compared to the equatorial plane in meiosis I.
<span>a. spinal cord
Spinal Cord is the part of the nervous system responsible for connecting the brain to the body.
</span>The nervous system is divided into two groups. The Central Nervous System and the Peripheral Nervous System.
The Central Nervous System involves the Brain and the Spinal Cord. Its contains the integrative and control centers.
<span>The Peripheral Nervous System involves the cranial nerves and spinal nerves. It is composed of the communication lines between the Central Nervous System and the rest of the body.</span>
Answer:
Alleles for feather colour exhibit incomplete dominance or co-dominance.
50% gray offspring + 50% black offspring
Explanation:
<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>
Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.
Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.
15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.
Bb x Bb = 1BB, 2Bb, and 1bb
Crossing the gray rooster (Bb) with a black hen (bb):
Bb x bb = Bb, Bb, bb, and bb
= 2Bb (gray):2bb (black)
50% of the offspring will be gray while the remaining 50% will be black.
