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omeli [17]
3 years ago
11

I need help I don’t know how to graph this

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

Attached: The red graph is a graph of g(x) = -2x + 2

The blue grap is the graph of g'(x) = -x/2 + 1

Step-by-step explanation:

To find the inverse of g(x) = -2x + 2

First replace g(x) with y;

y = -2x + 2

Then take y to the right and x to the left;

x = -2y + 2

Solving for y gives;

2y = -x + 2

y = -x/2 + 1

Replacing y now with g'(x) gives;

g'(x) = -x/2 + 1

The graphs of g(x) = -2x + 2 and its inverse are attached.

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Which value of P and Q result in an equation with no solutions? 83x+P=83x+Q
alekssr [168]

There is no number I can think of that would make the statement untrue.

The result of this when you subtract 83x from both sides leaves you with P = Q.

Unless you know differently, the equation says that P must equal Q no matter what x is. If there is such a condition, it is not obvious.

3 0
3 years ago
Find the distance between the two points. (5,-3) (-4,7)
STatiana [176]

Answer:

-9.4

Step-by-step explanation:

8 0
2 years ago
Solve this system of equations using substitution. Put your answer in ordered pair form, (x,y).
Gelneren [198K]
2x + 5y = 2
-3x - y =-3

-3x - y = -3
y = 3x - 3

substitute y = 3x - 3 into the first equation.

2x + 5y = 2
2x + 5(3x - 3) = 2
2x + 15x - 15 = 2
17x - 15 = 2

solve for x in 17x - 15 = 2

17x - 15 = 2
17x = 2 + 15
17x = 17
x = 1

substitute x = 1 into y = 3x - 3

y = 3x - 3
y = 3(1) - 3
y = 3 - 3
y = 0

(1, 0) << the answer

hope this helped, God bless!
8 0
3 years ago
Please help me!!! I will give brainliest to the person who explains their answer the best!!
Basile [38]

Answer:

I think elimination with subtraction would be the best answer choice, since all the numbers are positive.

5 0
2 years ago
Read 2 more answers
HELP WITH ALL PLZ I NEED HELP
alex41 [277]
1.) 16/100 and 0.16
2.) 7/10 and 0.7
3.) 6/10
4.) 73/100
5.) 6 9/10
6.)8 57/100
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8.)0.33
9.)7.20
10.)3.09
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14.)0.55
15.)D
I hope all of these are correct and help
4 0
3 years ago
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