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RoseWind [281]
3 years ago
9

AWARDED 40 POINTS Please help me

Mathematics
1 answer:
torisob [31]3 years ago
5 0
(A) 2/3A= -24
A= -24 • 2/3
A= 48/3
A= 16

(B) 20= -B/0.2
20 • 0.2= -B
4= -B
-4= B

(C) Distance between Point A & Point B is 20
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It reachs 5800 population in 1960 if i am not wrong. i'll check this out tomorrow right now i do not have enough time for it.

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3 years ago
? Divided by ? = 1/9
Elza [17]

Answer:

0.11

Step-by-step explanation:

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Alan sells custom made kites online. He makes a flat profit of $20 per kite, but he pays $20 per day for his website. Write an i
Afina-wow [57]
To pay website Alen needs to make 1 kite a day that is 7 kites.
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3 years ago
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Desmond's Desserts made a batch of fresh scones with 2/3 of a pound of butter and 1/2 of a
NemiM [27]

\frac{1}{6} or 0.167 pounds more butter was used than sugar

<em><u>Solution:</u></em>

Given that, Desmond's Desserts made a batch of fresh scones with 2/3 of a pound of butter and 1/2 of a  pound of sugar

<em><u>To find: Amount of butter used than sugar</u></em>

From given information,

\text{Butter used} = \frac{2}{3} \text{ pound }

\text{Sugar used } = \frac{1}{2} \text{ pound }

To find how much butter is used than sugar, find the difference between them

Difference = Butter\ used - Sugar\ used

Difference = \frac{2}{3} - \frac{1}{2}\\\\Difference = \frac{2 \times 2-1 \times 3}{3 \times 2}\\\\Difference =\frac{4-3}{6}\\\\Difference =\frac{1}{6} = 0.167\\\\

Thus \frac{1}{6} or 0.167 pounds more butter was used than sugar

5 0
3 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
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