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3 years ago

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Please please help me !!

1 answer:

Kamila [148]3 years ago

5 0

Step-by-step explanation:

you would plot each number in order that they are in. at 1 you would place 30 on the 30-34 area and so forth.

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F(x) = 3x+2<br><br> What is f(5)?

Ksju [112]

F(5)= 3.(5)+2=15+2=17

Another example: F(0)=3.(0)+2=0+2=2

You just replace the value in the two sides.

4 0

2 years ago

Find the quotient 7.4 ÷ 2647.72 *<br> 3578<br> 358<br> 357.8<br> 35.78

hoa [83]

Answer:

The answer is C. 357.8

Step-by-step explanation:

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3 0

3 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

3 years ago

Why does the following system of linear equations have no solution? x + 4y = 20 x + 4y = 16

Shkiper50 [21]

4y+4y=21x+16
8y=21x+16

7 0

3 years ago

The average THC content of marijuana sold on the street is 10.5%. Suppose the THC content is normally distributed with standard

MA_775_DIABLO [31]

a. This information is given to you.

b. We want to find

$\mathrm{Pr}\{X > 8.9\}$

so we first transform $X$ to the standard normal random variable $Z$ with mean 0 and s.d. 1 using

$X = \mu + \sigma Z$

where $\mu,\sigma$ are the mean/s.d. of $X$ . Now,

$\mathrm{Pr}\left\{\dfrac{X - 10.5}2 > \dfrac{8.9 - 10.5}2\right\} = \mathrm{Pr}\{Z > -0.8\} \\\\~~~~~~~~= 1 - \mathrm{Pr}\{Z\le-0.8\} \\\\ ~~~~~~~~ = 1 - \Phi(-0.8) \approx \boxed{0.7881}$

where $\Phi(z)$ is the CDF for $Z$ .

c. The 76th percentile is the value of $X=x_{76}$ such that

$\mathrm{Pr}\{X \le x_{76}\} = 0.76$

Transform $X$ to $Z$ and apply the inverse CDF of $Z$ .

$\mathrm{Pr}\left\{Z \le \dfrac{x_{76} - 10.5}2\right\} = 0.76$

$\dfrac{x_{76} - 10.5}2 = \Phi^{-1}(0.76)$

$\dfrac{x_{76} - 10.5}2 \approx 0.7063$

$x_{76} - 10.5 \approx 1.4126$

$x_{76} \approx \boxed{11.9126}$

5 0

2 years ago