Step-by-step explanation:
Simple interest formula

Compound interest formula

a.

Simple interest is $125
b
. 
Compound interest is $125
c. the result for both a and b are the same
d.

the simple interest is $375
e
. ![A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.025%7D%7B1%7D%29%5E%7B1%2A3%7D%5D%20%5C%5CA%3D5000%281.025%29%5E3%20%5C%5CA%3D5000%281.077%29%5C%5CA%3D%205385)
the compound interest is $385
f. the result compared, compound interest is $10 more than simple interest
g.

the simple interest is $600
h.
![A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869](https://tex.z-dn.net/?f=A%20%3D%205000%20%281%20%2B%20%5Cfrac%7B0.02%7D%7B1%7D%29%5E%7B1%2A6%7D%5D%20%5C%5CA%3D5000%281.12%29%5E6%20%5C%5CA%3D5000%281.9738%29%20%5C%5CA%3D%209869)
the compound interest is $4869
i. the result from g and h, h is over 8 times bigger than g.
j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h
Natural number
that is 1,2,3,4,5,6...
The answer to the question is 5 so CD=5
Answer:
6
Step-by-step explanation:
If V = IR, then V = 40 * 3 in this case, which means V = 120. Quote question, "Assume voltage remains constant." This means V still equals 120 in the second scenario, which we can input into I = V / R to make I = 120 / 20 = 6.
Hope this helps!