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Simora [160]
3 years ago
10

H(x)=2xsquared -3 what is the value of h(-4)?​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
8 0

Answer:

29

Step-by-step explanation:

h(x) = 2 * x^2 - 3

h(-4) = 2* (-4)^2 - 3

h(-4) = 2 * 16 - 3

h(-4) = 32 - 3

h(-4) = 29

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Which equation represents h(x)?
GarryVolchara [31]

Answer:

Step-by-step explanation:

You might find this easier if you change h(x) to y. It might look more familiar.

you are given 1 point and that is (-1,1). What that means is when x = -1,

y = 1

You have written this as though y is linear. It is not. The power is 1/3, not 1.

Let us try B which is what I think the answer is.

y = (x + 2)^(1/3)

Put x = -1 on the right hand side.

y = (-1 + 2)^(1/3)

y = (1)^(1/3)            

The cube root of 1 is 1.

So the answer is

y = (x + 2)^(1/3)

8 0
3 years ago
What is the range of y = sin θ ?
Tamiku [17]
The range of a function is the set of all the possible function outputs. We know that sin theta varies between -1 and 1 if we draw a graph. According to the graph, the largest number that is an output of g is -1, and the smallest number is 1. Every number between them is also an output of g for some input. Therefore, the range of g is [-1,1]. 
5 0
3 years ago
Graph the solution x
mixas84 [53]

Answer:

I think you need to put more info

Step-by-step explanation:


8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!
Bogdan [553]

Answer:

See the explanation.

Step-by-step explanation:

We are given the function f(x) = x² + 2x - 5

Zeros :

If f(x) = 0 i.e. x² + 2x - 5 = 0

The left hand side can not be factorized. Hence, use Sridhar Acharya formula and  

x= \frac{-2+\sqrt{2^{2}-4\times(-5)\times1 } }{2} and  

x= \frac{-2-\sqrt{2^{2}-4\times(-5)\times1 } }{2}

⇒ x = -3.45 and 1.45

Y- intercept :

Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.

Maximum point :

Not defined

Minimum point:  

The equation can be expressed as (x + 1)² = (y + 5)

This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis

Therefore, the minimum point is (-1,-5)

Domain :  

x can be any real number

Range:  

f(x) ≥ - 6

Interval of increase:

Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.

Therefore, interval of increase is +∞ > x > -1

Interval of decrease:

-∞ < x < -1

End behavior :  

f(x) = x^{2} +2x-5 =x^{2}  (1+\frac{2}{x} -\frac{5}{x^{2} } )

So, as x tends to +∞ , then f(x) tends to +∞

And as x tends to -∞, then f(x) tends to +∞. (Answer)

7 0
3 years ago
Ally ran 5 miles in 6 minutes. Sami ran 6 mile. If ally ran at a faster rate than Sami ,in how many minutes could Sami have run
Veseljchak [2.6K]
Answer:6 minutes
(not really sure that is what i got)
8 0
3 years ago
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