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liraira [26]
3 years ago
6

I have no idea how to do this. HELP ASAP (# 14)

Mathematics
1 answer:
NARA [144]3 years ago
4 0
Sorry i don’t understand how to do C but this is what i have and my work hope it helps :)

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Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C.   2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0
3 years ago
X - 2y + 2z = -22 <br> x + 3y - z = 03 <br> x + 2y + 3z = -15
scZoUnD [109]
What is your question?
7 0
3 years ago
Duke and Mary collect stamps. Duke has 1,364 stamps, and Mary has 1,808 stamps. How many stamps do they have in all?
Alex73 [517]

Answer:

Mary and Duke have 3,172 stamps altogether

1,364 + 1,808 = 3,172

8 0
3 years ago
Read 2 more answers
Find the equation of the tangent to the circle x2 + y2 = 109 at point (-10,3)
konstantin123 [22]

Answer:

10x - 3y = -109 .

Step-by-step explanation:

x^2 + y^2 = 109

Implicit Differentiation:

2x + 2y.y' = 0

y' = -2x/2y = -x/y

So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.

Equation of the tangent:

y - y1 = m(x - x1)

y - 3 = 10/3(x + 10)

y - 3 = 10/3 x + 100/3

3y - 9 = 10x + 100

-109 + 3y = 10x

10x - 3y = -109  

4 0
3 years ago
Evaluate the logarithmic expression Log subscript5^25 +log subscript 5^625/logsubscript5^100. The value of the expression, round
Lady bird [3.3K]
Hello !
Here are some rules for logarithms :    log ₐ b = n ⇔ aⁿ = b
                                                             log ₐ aⁿ = n
                                                             log ₐ (b·c) = logₐ b + log ₐ  c                                                                                                                  
                                                             log ₐ bⁿ = n· log ₐ b                                        ____________________________________________________
25=5²
625=5⁴
100 = 5² · 2²
____________________________________________________



(log₅ 25 + log₅ 625) / log₅100 =
 (log₅ 5²+ log₅ 5⁴) / log₅ (5² · 2²) =
 (log₅ 5²+ log₅ 5⁴) /( log₅ 5² + log₅ 2²) =
(2 + 4)/(2+log₅ 2² ) =
 6/ (2+2·log₅2)=
6/2 + 6/ (2·log₅2) =

3+ 3/log₅2
log₅2 = 0.5

So 3+ 3/log₅2 = 3 + 3/0.5 =3 + 6 = 9 

Answer : 9






3 0
3 years ago
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