Answers:
1. The n-intercept is 12. That means after 12 visits the amount of money on the gift car is $0.
2. The A(n)-intercept is 150. Before the visits, the amount of money on the gift car is $150.
Solution:
Amount of money on the gift card after n number of visits: A(n)=$150-$12.50 n
A(n)=150-12.50 n
1. n-intercept
A(n)=0→150-12.50 n =0
Solving for n: Subtracting 150 both sides of the equation:
150-12.50 n-150 = 0-150
-12.50 n = -150
Dividing both sides of the equation by -12.50:
(-12.50 n) / (-12.50) = (-150) / (-12.50)
n=12
The n-intercept is n=12; for n=12→A(12)=0. Point (n, A(n))=(12,0)
2. A(n) intercept
n=0→A(0)=150-12.50 (0)
A(0)=150-0
A(0)=150
The A(n) intercept is 150; for n=0→A(0)=150. Point (n, A(n))=(0,150)
That'd be 32 with no remainder.
-4(x + 1) + 5 = 17
Distribute -4 inside the parentheses.
(-4x - 4) + 5 = 17
Combine like terms (-4 + 5).
-4x + 1 = 17
Subtract 1 from both sides.
-4x = 16
Divide both sides by -4.
x = -4
Answer:
half way to the floor
Step-by-step explanation:
Hello,
Let y=sin^(-1)(12/13.
==>sin y=12/13
==>cos y=√(1-(12/13)²)=√(25/169)=5/13
Answer 5/13
