What is the answer to the multiplication problem 4×3

Explain the significance of the equation 100x -2y+ 400 = 0 which represents the hourly cost of a car repair.

Cerrena [4.2K]

Answer: The significance is that it is how much you will pay for the total repair which will help you know how much money you will spend.

Step-by-step explanation:

8 0

3 years ago

Write an equation in slope intercept form for the line that has a y intercept of 3 and a slope of -2

charle [14.2K]

Answer:

-2x + 3

Step-by-step explanation:

Trust me, this is the answer.

An explanation:

Slope is rate of change.

if the lady sells 2 cakes in 3 hours, her rate of change, or slope is 2/3.

Y-intercept is where the data enters the graph. It will not always be at the origin of the graph. If on the lady's first day of business, she sold 10 cakes, the Y-intercept is 10. This equation of the lady's business in slope intercept form would be 2/3x + 10. ALWAYS write the slope before x and the y intercept after the + or -- , hope this helps, but -2x + 3 is your answer for sure.

4 0

2 years ago

Find the value of X

olchik [2.2K]

<h3>Answer: 112</h3>

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Explanation:

The angle adjacent to the 146 degree angle is 180-146 = 34 degrees.

In other words, the angles 34 and 146 combine to 180. These angles are supplementary.

The tickmarks on this triangle tell us it is isosceles. The angles opposite the congruent sides are congruent angles. So the unmarked interior angles (not marked x) are 34 degrees each.

Now use the fact that any triangle has its interior angles always add to 180

x+34+34 = 180

x+68 = 180

x = 180-68

x = 112

5 0

2 years ago

Help!!! Find the slope and y-intercept

attashe74 [19]

Answer:

To find y-intercept: set x = 0 and solve for y. The point will be (0, y). To find x-intercept: set y = 0 and solve for x. The point will be (x, 0).

Step-by-step explanation:

4 0

1 year ago

Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).

Arisa [49]

The distance between a point $(x,y,z)$ on the given plane and the point (0, 2, 4) is

$\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}$

but since $\sqrt{f(x,y,z)}$ and $f(x,y,z)$ share critical points, we can instead consider the problem of optimizing $f(x,y,z)$ subject to $x-2y+3z=6$ .

The Lagrangian is

$L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)$

with partial derivatives (set equal to 0)

$L_x=2x+\lambda=0\implies x=-\dfrac\lambda2$
$L_y=2(y-2)-2\lambda=0\implies y=2+\lambda$
$L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2$
$L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6$

Solve for $\lambda$ :

$x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6$
$\implies2=7\lambda\implies\lambda=\dfrac27$

which gives the critical point

$x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7$

We can confirm that this is a minimum by checking the Hessian matrix of $f(x,y,z)$ :

$\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}$

$\mathbf H$ is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

$\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}$

8 0

2 years ago