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RSB [31]
3 years ago
8

A concentrated solution contains a large proportion of solute relative to the solvent. true or false

Chemistry
1 answer:
Leto [7]3 years ago
7 0

The statement “A concentrated solution contains a large proportion of solute relative to the solvent.” is true. It means that the amount of solute molecules present in that solution is greater than the amount of solvent molecules present in that solution.

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What salivary glands are responsible for the beginning of the digestion of food?
Komok [63]
I think this what you're looking for http://www.webmd.com/oral-health/salivary-glands
8 0
4 years ago
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
inn [45]

Answer:

m_{steel}=54.47gSteel

Explanation:

Hello,

In this case, one considers that the heat lost by the water is gained by the steel rod:

\Delta H_{water}=-\Delta H_{steel}

That in terms of masses, heat capacities and temperatures is:

m_{water}Cp_{water}(T_F-T_{water})=-m_{steel}Cp_{steel}(T_F-T_{steel})

Thus, solving for the mass of the steel rod, we obtain:

m_{steel}=\frac{m_{water}Cp_{water}(T_F-T_{water})}{-Cp_{steel}(T_F-T_{steel})} \\\\m_{steel}=\frac{125mL*\frac{1g}{1mL}*4.18\frac{J}{g^oC} (22.00^oC-21.10^oC)}{-0.452\frac{J}{g^oC}*(2.00^oC-21.10^oC)} \\\\m_{steel}=54.47gSteel

Best regards.

6 0
4 years ago
Scientific Notation and Significant Figures Problem:
solong [7]

Answer:

84130.44698 and 8.413044698*10^4

Explanation:

8 0
3 years ago
5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
A sample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of metha
LUCKY_DIMON [66]
The  amount of heat required   is calculated  using the below  formula

Q(heat) =M(mass) xC(specific heat capacity)x delta T (change in temperature)

change in the temperature in kelvin=(35+273)- (25 +2730= 10K
c= 2.48 j/g/k
mass= 54.0 g

Q= 54.0 g x 2.48 j/g/k x 10k  = 1339.2  joules is required
3 0
4 years ago
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