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NeX [460]
4 years ago
9

Chapter 2 test chemistry

Chemistry
1 answer:
____ [38]4 years ago
6 0

Im sorry but Chapter 2 test chemistry doesnt sound much like a question can you be more specific thanks ik u can be more specififc!

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Q # 1 For chemical reaction ,please help
horrorfan [7]

Answer:- d)  42 kJ of heat is released and the reaction is exothermic.

Solution:- Heat of reaction is the summation of heats of products - reactants.

\Delta H_r_x_n=\sum [products-reactants]

From given information, the energy contained by products is 352 kJ and the energy contained by reactants is 394 kJ. Let's plug in the values in the formula:

\Delta H_r_x_n  = [352 kJ - 394 kJ]

\Delta H_r_x_n  = -42 kJ

Heat of reaction is -42 kJ. The negative sign indicates the heat is released means the reaction is exothermic.  

So, the correct option is the last one, 42 kJ of heat is released and the reaction is exothermic.

5 0
3 years ago
Why will nuclear fission probably never be used directly for powering automobiles?
solmaris [256]

Answer:

IT would not

Explanation:

because the design would be too bulky and would be very unsafe.

3 0
3 years ago
Carbon-14 has more ____
kolbaska11 [484]

Answer:

The second one

Neutrons

8 0
3 years ago
Look carefully at the animation. The moving items represents electrons.
blondinia [14]
Electrons attract objects and pull toward
7 0
4 years ago
The number of grams of H2 in 1470 mL of H2 gas. ​
Lorico [155]

Answer:

0.1313 g.

Explanation:

  • It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
  • Suppose that hydrogen behaves ideally and at STP conditions.

<u><em>Using cross multiplication:</em></u>

1.0 mol of hydrogen occupies → 22.4 L.

??? mol of hydrogen occupies → 1.47 L.

∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.

  • Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:

<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>

5 0
3 years ago
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