P1 * V1 ÷ T1 = P2 * V2 ÷ T2
45 * 1.20 ÷ 314 = 96 * V2 ÷ 420
30,144 * V2 = 22,680
V2 = 22,680 ÷ 30,144
The new volume is approximately 0.75 liter.
I hope I helped
Answer:
O B. Convert the 10 g of NaCl to moles of NaCl.
Explanation:
The formula for finding the molality is m=moles of solute/kg of solvent. The solute for this question is NaCl and the solvent is water.
(10g NaCl)(1 mol NaCl/58.44g NaCl)=0.1711 mol NaCl
58.44 is the molar mass of NaCl
m=0.1711 mol NaCl/2 kg H2O
m=0.085557837
Answer:
I hope this picture helps you
Explanation:
Answer:
<em>2.54 mol CO2 </em>
Explanation:
To calculate the mol of carbon dioxide that will be generated by megajoule (MJ). First, we have to find the value of the formation enthalpy for the CO2 at standard conditions.
<em>Remember that standard conditions are at 25°C and 1 atm. </em>
Any physic chemistry book has the table of ΔHf°, I always use one name Levine's physic chemistry. You can trust its data.
Enthalpy of formation for CO2: -393.509 kJ/mol
As you can see this value means that for each 393.509 kJ liberate (that's indicated for the menus sing), 1 mol of CO2 is formed.
Let's write this using mathematic language:
393.509 kJ/ 1 mol CO2
The problem asks you to find how many mols are produced by 1 megajoule liberate, let's change megajoule to kilojoule.
1 megajoule (MJ) = 1000 kJ
1000 kJ x (1mol/ 393.509 kJ) = 2.54 mol CO2
<em>Remember don't use the negative value to make the calculus. The negative value just indicates that the heat is been released.</em>
If you want to watch the mathematics details, go to the image attached.