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BigorU [14]
3 years ago
10

Please help!! i need the answer ASAP!

Chemistry
1 answer:
nirvana33 [79]3 years ago
7 0

Answer:

23.34 %.

Explanation:

  • The percentage of water must be calculated as a mass percent.
  • We need to find the mass of water, and the total mass in one mole of the compound. For that we need to use the atomic masses of each element and take in consideration the number of atoms of each element in the formula unit.
  • <em>Atomic masses of the elements:</em>

Cd: 112.411 g/mol, N: 14.0067 g/mol, O: 15.999 g/mol, and H: 1.008 g/mol.

  • <em>Mass of the formula unit:</em>

Cd(NO₃)₂•4H₂O

mass of the formula unit = (At. mass of Cd) + 2(At. mass of N) + 10(At. mass of O) + 8(At. mass of H) = (112.411 g/mol) + 2(14.0067 g/mol) + 10(15.999 g/mol) + 8(1.008 g/mol) = 308.5 g/mol.

  • <em> Mass of water in the formula unit:</em>

<em>mass of water</em> = (4 × 2 × 1.008 g/mol) + (4 × 15.999 g/mol) = 72.0 g/mol.

  • <em>So, the percent of water in the compound = [mass of water / mass of the formula unit] × 100 = [(72.0 g/mol)/(308.5 g/mol)] × 100 = 23.34 %</em>
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In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

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Explanation:

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