Answer:
Option C. By increasing the temperature
Explanation:
From the graphical illustration above, we see clearly that the volume and temperature of the gas are directly proportional. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume will also decrease. This can further be explained by using the ideal gas equation as shown below:
PV = nRT
P is the pressure.
V is the volume.
n is the number of mole.
R is the gas constant.
T is the temperature.
PV = nRT
Divide both side by P
V = nRT/P
Since n and P are constant, the equation above becomes:
V & T
V = KT
K is the constant.
The above equation i.e V = KT implies that:
As T increases, V will also increase and as T decreases, V will also decrease.
Considering the question given above,
The volume of the gas can be increased if the temperature is increased.
Answer: 0.024 M
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.12 M
= volume of stock solution = 20.0 ml
= molarity of diluted solution = ? M
= volume of diluted solution = 100.0 ml
Putting in the values we get:
Therefore, the concentration of the resulting solution is 0.024 M.
The ph of a solution is 3.7
Solution:
According to the equaiton of Henderson-Hasselback
pH= pKa+ log(salt/acid)
here it is given the value of
pKa= 4.7
So,
pH = pKa+ log(0.1/0.01)
= 4.7 + log(0.1)
= 4.7–1
= 3.7.
The following problem illustrates how the Henderson-Hasselbalch equation can be used to determine how much acid and conjugate base should be combined to create a buffer solution with a specific pH.
To learn more click the given link
brainly.com/question/13423434
#SPJ4
Answer:
n₁ = 1.0× 10⁻⁴ mol
Explanation:
Given data:
Initial volume of balloon = 230 mL
Initial number of moles of He =?
Final number of moles of He = 3.8 × 10⁻⁴ mol
Final volume of balloon = 860 mL
Solution:
The given problem will be solve through Avogadro law,
"Number of moles of gas and volume are directly proportional to each other at constant temperature and constant pressure"
Mathematical relationship:
V₁/n₁ = V₂/n₂
No we will put the values.
230 mL /n₁ = 860 mL/ 3.8 × 10⁻⁴ mol
n₁ = 230 mL× 3.8 × 10⁻⁴ mol/ 860 mL
n₁ = 874 × 10⁻⁴ mol. mL / 860 mL
n₁ = 1.0× 10⁻⁴ mol
1.The reactants must collide
2.The reactants must collide with sufficient energy to react
3.The reactants must collide in the correct orientation
