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nadya68 [22]
3 years ago
10

4. Calorimetry can be used to determine the specific heat capacity of different substances (not just metals). Using the online c

alorimeter simulation you perform the following calorimetry experiment: 100g of ethanol at 50.0°C is mixed with 100. g of water at 20.0°C. After mixing the temperature is 31.11°C. Calculate the specific heat capacity of ethanol.
In problem #4 you calculated the specific heat capacity of ethanol from data obtained using the online calorimeter simulation. When you try the same experiment in a real calorimeter, the final temperature after mixing is 34.00°C. Offer an explanation for why the final temperatures are different. Hint: the calorimeter simulation may be missing something.
Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
8 0

Answer:

the specific heat capacity of ethanol is 2.4608 J/g°C

The variation in the final temperature is due to the rate of heat lost. Calorimeters do not dissipate or absorb energy

Explanation:

the solution is in the attached Word file

Download docx
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Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
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Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

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R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

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T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

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So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

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Answer:

The answer is option 3.

Explanation:

When salt is added to the water, the boiling point increases because it needs to take in more energy from heat to <u>b</u><u>r</u><u>e</u><u>a</u><u>k</u><u> </u><u>d</u><u>o</u><u>w</u><u>n</u> the bonds and dissolve the salt in the water.

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20 points! &lt; is what I chose. How did I do?
Zigmanuir [339]

Greenhouse gases released from the burning of fossil fuels are responsible for global warming.

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Explanation:

This is correct!

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