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nadya68 [22]
3 years ago
10

4. Calorimetry can be used to determine the specific heat capacity of different substances (not just metals). Using the online c

alorimeter simulation you perform the following calorimetry experiment: 100g of ethanol at 50.0°C is mixed with 100. g of water at 20.0°C. After mixing the temperature is 31.11°C. Calculate the specific heat capacity of ethanol.
In problem #4 you calculated the specific heat capacity of ethanol from data obtained using the online calorimeter simulation. When you try the same experiment in a real calorimeter, the final temperature after mixing is 34.00°C. Offer an explanation for why the final temperatures are different. Hint: the calorimeter simulation may be missing something.
Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
8 0

Answer:

the specific heat capacity of ethanol is 2.4608 J/g°C

The variation in the final temperature is due to the rate of heat lost. Calorimeters do not dissipate or absorb energy

Explanation:

the solution is in the attached Word file

Download docx
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During an experiment, ice and water were placed in a perfectly insulated thermos flask at 0 °C. Describe this system when it pha
Ivanshal [37]

Answer :By the time thermal equilibrium is attained in the system, ice is completely converted to water.

What is tehrmal equilibrium?

Thermal equilibrium is a situation in which two substances are exactly at the same temperature. That is. Heat is no longer flowing beween the bodies.

Recall that an insulated thermos flask implies that heat does not eneter or leave the system. Heat will flow from the water to the ice untill the both attains the same temperature and the ice is completely converted to water.

Have a good day

5 0
2 years ago
5. 1.00 mol HNO3 is treated with 4.47 g of magnesium. Calculate the number of moles of
ruslelena [56]

Answer:

The balanced equation is:

2 HNO3 + Mg ---> Mg(NO3)2 + H2

From the equation, we can see that we need twice the moles of HNO3 than the moles of Mg

Moles of Mg:

Molar mass of Mg = 24 g/mol

Moles = Given mass / Molar Mass

Moles of Mg = 4.47 / 24 = 0.18 moles (approx)

Hence, 2(moles of Mg) = 0.36 moles of HNO3 will be consumed

Number of moles of HNO3 after the reaction is finished is the number of unreacted moles of HNO3

Unreacted moles of HNO3 = Total Moles - Moles consumed

Unreacted moles of HNO3 = 0.64 moles (approx)

Since we approximated the value of moles of Mg, the value of remaining moles of HNO3 will also be approximate

From the given options, we can see that 0.632 moles is the closest value to our answer

Therefore, 0.632 moles will remain after the reaction

3 0
3 years ago
Find the linear function Cequals​f(F) that gives the reading on the Celsius temperature scale corresponding to a reading on the
padilas [110]

Answer:

C = (5/9) F - (160/9)

They both read equal at Z = - 40

Explanation:

We are looking for a linear function so we can write the following condition

Y = aX + b

Applying it to the exercise we got C = a F + b

Let's use the facts that C = 0 when F = 32 and C = 100 when F = 212

0 = 32 a + b            (1)

100 = 212 a + b       (2)

From (1) b = - 32 a , when we replace this in (2) we obtain a = (5/9)

and b = - (5/9)32 = - 160/9

Finally the linear function is C = (5/9) F - (160/9)

Both readings are equal at a Z number so

Z = (5/9) Z - 160/9

(4/9) Z = -160/9 and Z = - 40

6 0
3 years ago
What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0
3 years ago
Which statement describes streak?
Oliga [24]

Answer:

Streak is tested by scraping a mineral across plate

Explanation: Hope this helps :)

5 0
3 years ago
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