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r-ruslan [8.4K]
3 years ago
15

Anaylze: 5 + 3g when g=7

Mathematics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer:

=26

Step-by-step explanation:

5+3(7)

5+21

=26

vazorg [7]3 years ago
4 0

Answer: then the equation basically is 5+3x7  you just need to subsitute the 7 in the problem

Step-by-step explanation:Hope this helps!

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Question 16 (1 point) (04.05 MC) The graph shows a journey in a car. Which of the statements most likely describes the start of
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Answer:

honestly i think it might be (C)

Step-by-step explanation:

4 0
3 years ago
Total consumption of fruit juice in a particular country in 2006 was about 1.85 billion gallons. The population of that country
Eduardwww [97]

Given :

Population of country in 2006 , P = 300 million.

Consumption of fruit juice in 2006 by while population, C = 1.85 billion.

To Find :

The average number of gallons of fruit juice consumed per person in the country in​ 2006.

Solution :

We know, 1 billion = 1000 million.

C = 1.85 billion = 1850 million.

Now, average umber of gallons of fruit juice consumed per person in the country in​ 2006 is :

c =\dfrac{C}{P}\\\\c=\dfrac{1850}{300}\ gallons/person\\\\c=6.17 \ gallons/person

Hence, this is the required solution.

4 0
3 years ago
A summer camp is organizing a hike and needs to buy granola bars for the campers. The granola bars come in small boxes and large
pychu [463]

Answer: 306

Step-by-step explanation:

8 0
3 years ago
Chris plans to mulch the Border surrounding a rectangular Garden in his backyard if the length of L of the garden (exculding its
Naya [18.7K]
The answer by the sequence:

Width of the garden = w
Length of the garden  = 2w+3

Width of the entire plot = w + 0.5w = 1.5w
Length of the entire plot = (2w + 3) 0.5w = 2.5w + 3

Area of the garden = w (2w + 3) 
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Area of the garden = 2w² + 3w
Area of the entire plot = 3.75w² + 4.5w

Area of border = area of the entire plot - area of the garden
                          = 3.75w² + 4.5w - (2w² + 3w)

Area of the border = 3.75w² + 4.5w - 2w² - 3w

Area of the border = 1.75w² + 1.5w
3 0
3 years ago
Two isosceles triangles share the same base. Prove that the medians to this base are collinear. (There are two cases in this pro
Anna71 [15]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

 ∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.




3 0
3 years ago
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