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3 years ago

Predict the Solubility of the following substances in water.

1 answer:

5 0

a. NaNO3: soluble
b. AgBr: insoluble
c. NH4OH: soluble
d. Ag2CO3: insoluble
e. NH4Br: soluble
f. BaSO4: insoluble
g. Pb(OH)2: soluble
h. PbCO3: insoluble

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CuFeS2 + 3 CuCl2 --> 4 CuCl + FeCl2 + 2 S How many mL of 0.075 M CuCl2 are needed to titrate 0.20 grams of CuFeS2?

GuDViN [60]

Answer:

$V_{CuCl_2 }= 43.6mL$

Explanation:

Hello there!

In this case, according to this titration problem, it is possible to note there is a 1:3 mole ratio of CuFeS2 to CuCl2; it means that we can use the following equation:

$3*n_{CuFeS_2}=n_{CuCl_2 }$

Thus, by introducing the mass and molar mass of the former and the volume and concentration of the latter, we write:

$3*0.20gCuFeS_2*\frac{1mol}{183.51g} =V_{CuCl_2 }*0.075\frac{mol}{L} \\\\V_{CuCl_2 }=\frac{0.00327mol}{0.075mol/L}*\frac{1000mL}{1L} \\\\V_{CuCl_2 }= 43.6mL$

Regards!

5 0

2 years ago

Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 l of carbon dioxide at 20.0 Â°c an

kvv77 [185]

Answer:

Percentage by mass of calcium carbonate in the sample is 93.58%.

Explanation:

Assumptions:

calcium carbonate was dissolved completely and the amount of carbon dioxide released was proportional to the amount of calcium carbonate.
the sample did not contain any other compound that released or reacted with carbon dioxide.

$PV = nRT$

$n = \frac{PV}{RT}$

$P = 791 mmHg = \frac{791 mmHg}{760 mmHg} x 1 atm = 1.040789 atm.$

$R = 8.314 \frac{J}{K*mol} = 0.082 \frac{L*atm}{K*mol}$

$T = 20^{0}C + 273^{0} C = 293 K$

$n = \frac{1.040789 atm * 1.14 L}{0.082 \frac{L * atm}{K * mol} * 293 K }$

$n = 0.0493839 mol.$

given the equation of the reaction:

$CaCO_{3} + 2HCL = CaCl_{2} + CO_{2} + H_{2}O$

from assumption:

amount carbon dioxide = amount of calcium carbonate

$n(CaCO_{3} ) = n(CO_{2} )$

reacting mass ( m ) = Molar Mass ( M ) * Amount ( n )

$m(CaCO_{3} ) = n(CaCO_{3} ) * M(CaCO_{3} )$

m = 0.04938397 $mol$ * 100 $\frac{g}{mol}$ = 4.93839 $g$

percentage by mass of CaC $O_{3}$ = $\frac{mass of pure }{mass of impure}*100 = \frac{4.93839g}{5.28g}*100 = 93.5802%$ .

8 0

2 years ago

Is this soulution acidic or basic Ph= 12 Basic Acidic

BaLLatris [955]

Answer:

basic

Explanation:

ph>7 soits basic not acidic

7 0

2 years ago

Read 2 more answers

Which of the following always changes when transmutation occurs?

mart [117]

Answer:

The atomic number

Explanation:

Transmutation refers to the conversion of one chemical element into another. A transmutation usually involves a change in the structure of atomic nuclei and this may be induced by a nuclear reaction.

Transmutation was first achieved in 1919 by Lord Rutherford when he successfully changed a nitrogen nucleus to an oxygen-18 isotope, producing a proton in the process.

Since transmutation often involves changing one atom into another, the atomic number or mass number of the original element always changes (to form a new element) in the process.

3 0

2 years ago

423.3 mL of gas is at 49.2 C. It is compressed to a volume of 79 mL. What is the new temperture. Express your answer in Kelvin.

zzz [600]

Answer: 60.1K

Explanation:

Initial volume of gas V1 = 423.3mL

Initial temperature T1 = 49.2°C

Convert temperature in Celsius to Kelvin

( 49.2°C + 273 = 322.2K)

Final temperature T2 = ?

Final volume V2 = 79mL

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

423.3mL/322.2 = 79mL/T2

To get the value of T2, cross multiply

423.3mL x T2 = 322.2K x 79mL

423.3mL x T2 = 25453.8

T2 = (25453.8/423.3mL)

T2 = 60.1K

Thus, the new temperature of the gas is 60.1K

8 0

3 years ago