There are 3 moles of
![NH_4^+](https://tex.z-dn.net/?f=NH_4%5E%2B)
<span>per 1 mole of salt and 1 mole of
![PO_{4}^{3-}](https://tex.z-dn.net/?f=PO_%7B4%7D%5E%7B3-%7D)
</span>per mole of salt, the total ionic concentrations must be
![2.7 M](https://tex.z-dn.net/?f=2.7%20M)
of
![NH_4^{+}](https://tex.z-dn.net/?f=NH_4%5E%7B%2B%7D)
, and
![0.9 M](https://tex.z-dn.net/?f=0.9%20M)
of
The formula of hydrated copper(II) sulfate is CuSO4.10H2O
<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>
The formula of the hydrated copper (ii) sulfate is determined as follows:
Mass of hydrated salt = 12.5 g
Mass of anhydrous salt = 8.0 g
Mass of water = 12.5 - 8 = 4.5 g
mole ratio of water and anhydrous salt is;
4.5/18 : 8.0/159.5
0.562 : 0.05
10 : 1
Water of crystallization (n) = 10.
Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O
Learn more about water of crystallization at: brainly.com/question/26146814
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Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
<span>P1V1M1/m1T1 = P2V2M2/m2T2 </span>
<span>Since P, M and T are constant, the equation becomes </span>
<span>V1/m1 = V2/m2 </span>
<span>Now plug in your values and solve for V2</span>
Answer:
A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.
Explanation:
The electronegativity from H is 2.2, from C is 2.55 and from O is 3.44. This property is the measure of the attractive force between an atom and a pair of electrons.
So, the difference of electronegativity of H and C is smaller than the difference between O and C. Because oxygen is more electronegative, the electrons stay close to it in the bond C=O. So carbon has a partial positive charge in that bond. For the bond C-H, the shared electrons stay closes to carbon.