Answer:
pH = 11.216.
Explanation:
Hello there!
In this case, according to the ionization of ammonia in aqueous solution:
We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:
However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:
Which is also:
Thereafter we can compute the pOH first:
Finally, the pH turns out:
Regards!