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3 years ago

What is the molarity of a solution containing 56 grams of solute in 959 mL of solution?

1 answer:

5 0

Molarity refers to the MOLES of solute per litre of solvent. We're given a volume of solvent, but a mass of solute. We need to convert mass to moles, and the way to do that is using the molar mass of the solute. This question can't be answered unless we know the molar mass of the solute.

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The pressure of a gas is 750 torr when its volume is 400. ml. Calculate the

ololo11 [35]

Answer:

a. 0.66 atm

Explanation:

Pi = 750 torr = 0.99 atm. Pf = ?

Vi = 400 ml Vf = 600ml

Using PiVi = PfVf

Then 400ml × 0.99atm = Pfatm × 600ml

Solving for Pf, we have,

Pf = (400ml × 0.99atm)/600ml

Pf = 0.66atm

7 0

2 years ago

Four different solutions have the following boiling points. Which boiling point corresponds to a solution with the lowest freezi

UNO [17]

What are the temperatures?

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3 years ago

Does iron always have a charge of 2+ when it forms an ion

Usimov [2.4K]

Answer:

Roman numeral notation indicates charge of ion when element commonly forms more than one ion. For example, iron(II) has a 2+ charge; iron(III) a 3+ charge.

Explanation:

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3 years ago

An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh

Finger [1]

Answer:

The beaker holds 307.94 mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

weight of water (m) = total weight - weight of beaker

Empty weight of beaker = 25.91 g

Weight of beaker with water = 333.85 g

Weight of water = 333.85 - 25.91 = 307.94 g

Density of water = 1 g/mL

We have

Mass = Volume x density

307.94 = Volume x 1

Volume = 307.94 mL

The beaker holds 307.94 mL

3 0

3 years ago

If we test the solubility of Salt, Sugar, and Epsom Salt then what will dissolve the most

aniked [119]

Answer:

kdkdxkxjdixndjxnksnxks xnxbc

Explanation:

bzjzxbdjx dmxkemcneovmidc.kdncdjxndjxncjb

4 0

3 years ago