Ammonia (NH3) boils at -33∘C; at this temperature it has a density of 0.81 g/cm3. The enthalpy of formation of NH3(g) is -46.2 k
1 answer:
Answer:
-87098.82kJ
Explanation:
Hello,
This process could be attained into two steps due to the specified conditions at assuming that it is at -33°C at the beginning:
ΔΔ
Δ
Thus:
Δ
Once the ammonia is gaseous, the burning chemical reaction is:
So the enthalpy of reaction for the given amount of ammonia is:
Δ
Finally, the total enthalpy is:
Δ
Best regards.
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Since germanium has 4 electrons in its outer most shell so it needs 4 more electrons to complete its octet and attains the stability. Hydrogen has 1 electron in its outer most shell and it needs only 1 electron to attain stability so, each germanium will combine with 4 hydrogen atoms and thus forming molecule which is stable in nature.
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Answer: pH of resulting solution will be 13
Explanation:
pH is the measure of acidity or alkalinity of a solution.
Moles of ion =
Moles of ion =
For neutralization:
1 mole of ion will react with 1 mole of
ion
0.01 mol of ion will react with =
of
ion
Thus (0.012-0.01)= 0.002 moles of are left in 20 ml or 0.02 L of solution.
Thus the pH of resulting solution will be 13