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egoroff_w [7]
3 years ago
9

The contingency table below gives the counts of students by activities and gender. Band Sports Debate Total Male 105 320 7 432 F

emale 105 160 14 279 Total 210 480 21 711 If a student is randomly selected, what is the probability that a student is female or plays sports?
Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

599/711

Step-by-step explanation:

           Band Sports Debate Total

Male     105 320  7         432

Female 105 160         14         279

Total 210 480          21          711


P(female or plays sports)

We want the probability that they are female or play sports, but we cannot double count the female sports players, so we subtract them

 P(female) + P (sports) - (female and sports)

female/total + sports/total - female sports/ total

279/711 + 480/711 - 160/711

599/711

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2(3 + x) = 6 + 2x cual es la propiedad ?
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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of
sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028

b) Probability that exactly 2 has only cats (p=0.15)

P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759

c) Probability that exactly 1 has cats and dogs (p=0.1)

P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508

8 0
3 years ago
Estimate
Taya2010 [7]
126/10 would mean that from the original number, the decimal point is at 126.0 so when it is divided by 10, it will move over one placement, making it 12.6... I would estimate that your answer is C. 12.6
5 0
3 years ago
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