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Alecsey [184]
3 years ago
7

Graph y=6x−7 Identify the x-intercept.

Mathematics
1 answer:
valina [46]3 years ago
6 0

9514 1404 393

Answer:

  x-intercept: 7/6

Step-by-step explanation:

The x-intercept is found by solving for x when y=0.

  0 = 6x -7

  7 = 6x . . . . . add 7 to both sides of the equation

  7/6 = x . . . . divide both sides by 6

The x-intercept is 7/6 = 1 1/6 ≈ 1.167.

__

The y-intercept is the constant in the given equation: -7. The slope of 6 tells you the line rises 6 units for 1 unit to the right. So, the point (1, -1) is another point on the graph. The line through those two points, (0, -7) and (1, -1), will intersect the x-axis at x=7/6.

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85°<br> 4x + 21°<br> what do I am suppose
ValentinkaMS [17]

Answer:

x= 16

4x+21 = 85 degrees

Step-by-step explanation:

The angles shown are vertical angles and vertical angles are equal

85 = 4x+21

Subtract 21 from each side

85 -21 = 4x+21-21

64 = 4x

Divide by 4

64/4 = 4x/4

16 = x

4 0
3 years ago
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What’s the correct answer for this?
Makovka662 [10]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

A tangent meets with the radius to form a right angle

Thus, we can use Pythagoras' theorem

b^2 = c^2 - a^2

Sub the values in:

b^2 = 5^2 - 3^2

b^2 = 16

Square root for the answer:

b = 4

Thus, the answer is option A.

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8 0
3 years ago
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You find 72 coins consisting only of nickels, dimes, and quarters, with a face value of $10.20. However, the coins all date from
Oliga [24]

Answer:

You have found 24 nickels.

Step-by-step explanation:

Let N be the number of nickles, D be the number of dimes and Q be the number of quarters. The number of coins and their face values are given by the following expressions, respectively:

N+D+Q=72\\0.05N+0.10D+0.25Q=10.20

As of now we have three variables and two expressions, the final expression needed to solve the linear system is given by the amount offered by the coin dealer:

10N+20D+15Q=1,060

Solving the linear system:

N+D+Q=72\\5N+10D+25Q=1,020\\10N+20D+15Q=1,060\\\\10N-10N+20D-20D+15Q-50Q=1,060-(2*1,020)\\-35Q=-980\\Q=28\\\\5N-10N+10D-10D+25Q-10Q=1,020-720\\-5N+15Q=300\\-5N=300-(15*28)\\N=24

You have found 24 nickels.

7 0
3 years ago
What are the first, second, and third frequencies audible from a 20 cm long organ pipe when (A) only one end is open and when (B
kotykmax [81]
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz

The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz


2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz


3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz


B) The answers are:

the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz

The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz


2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz


3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
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Ghella [55]

Answer:

27

Step-by-step explanation:

To get the median, we line the values up from lowest to greatest.

23, 25, 25, 27, 32, 35, 36

What's the number in the middle? Since there's an odd number of values, it's easier to see: the median is 27.

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