2 years ago

A sequence is defined recursively by f(1) = 16 and f(n) = f(n-1) + 12 find f(4)

1 answer:

8 0

$f(1)=16\\
f(n)=f(n-1)+12\\\\
f(2)=f(2-1)+12=f(1)+12=16+12=28\\
f(3)=f(3-1)+12=f(2)+12=28+12=40\\
f(4)=f(4-1)+12=f(3)+12=40+12=52\\\\
\boxed{f(4)=52}
$

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