Question

A sequence is defined recursively by f(1) = 16 and f(n) = f(n-1) + 12 find f(4)

Answer 1

$f(1)=16\\ f(n)=f(n-1)+12\\\\ f(2)=f(2-1)+12=f(1)+12=16+12=28\\ f(3)=f(3-1)+12=f(2)+12=28+12=40\\ f(4)=f(4-1)+12=f(3)+12=40+12=52\\\\ \boxed{f(4)=52}$