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kolbaska11 [484]
4 years ago
15

I am doing solving by elimination for Algebra 1 and I am lost here is the question

Mathematics
2 answers:
Brums [2.3K]4 years ago
5 0
You have to rearrange into the format y=mx+b.
natali 33 [55]4 years ago
5 0
-2y=-2+3x
y=1+3/-2x

-2(x)-3(1+3/-2 x ) = -13
-2(x)-3+9/2x+13=0
5/2 x + 10 = 0
5/2 x = -10
x = -4
_______
-2(-4)-3y=-13
8-3y=-13
-3y=-21
y = 7
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AB=\left[\begin{array}{cc}32&1&18&-22\\\end{array}\right]

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To multiply matrices, we need to take the dot product of each row and column.

First, the dot product of (1,5) and (2,6) is what goes in the top-leftmost section of the resulting matrix. So the dot product would be (1*2)+(5*6)=2+30=32.

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Third, the dot product of (-3,4) and (2,6) is what goes in the bottom-leftmost section of the resulting matrix. So the dot product would be (-3*2)+(4*6)=-6+24=18.

Fourth, the dot product of (-3,4) and (6,-1) is what goes in the bottom-rightmost section of the resulting matrix. So the dot product would be (-3*6)+(4*-1)=-18-4=-22.

Therefore, the resulting matrix is \left[\begin{array}{cc}32&1&18&-22\\\end{array}\right]

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