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IrinaVladis [17]
3 years ago
10

Paul used 3/4cup of butter in a batch of brownies. He ate 1/6 of the batch of brownies. What fraction of a cup of butter did he

consume when he ate the brownies? Use math drawings and explain in detail how your drawings help you solve this problem
Mathematics
1 answer:
Ronch [10]3 years ago
8 0
The answer is 1/8 cups. you have to take 1/6 of 3/4.
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Expanded form using fractions 1/100
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Answer:

Standard form: 1

Step-by-step explanation

expanded notation form: 1

expanded factors form: 1x1

expanded exponential for 1x 10^0

4 0
3 years ago
The given line passes through the points (0, −3) and (2, 3).
Alex Ar [27]
Well, parallel lines have the same exact slope, so hmmm what's the slope of the one that runs through <span>(0, −3) and (2, 3)?

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 0 &,& -3~) &#10;%  (c,d)&#10;&&(~ 2 &,& 3~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-3)}{2-0}\implies \cfrac{3+3}{2-0}\implies 3
<span>
so, we're really looking for a line whose slope is 3, and runs through -1, -1

</span>\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1\\&#10;%  (a,b)&#10;&&(~ -1 &,& -1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies 3&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)]&#10;\\\\\\&#10;y+1=3(x+1)<span>
</span>
8 0
3 years ago
Read 2 more answers
What is 56.23 × 104 in standard form?
aleksklad [387]

Answer:

5.23×10^5

Step-by-step explanation:

You mean 56.23×10^4?

That would be 5.623×10×10^4, or 5.23×10^5

4 0
3 years ago
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Zach is 3 years older than twice his sister Maya’s age.
Flauer [41]
The answer is z=2m+3 so the first one is right
8 0
3 years ago
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98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))
IgorLugansk [536]
That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

A(-16.55\cos 25, -16.55 \sin 25)

B=A+(5 \cos 53, 5 \sin 53)

C=B+(20,0)

C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)

C \approx (8.00968, -10.9875) \approx(8,-11)

Your team takes the direct path at a constant speed of 6 miles per hour.

<span>Our team.  T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}

</span><span>Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}

Team Blue follows the riddle and travels at a constant speed of 10 mph.

</span>T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}
<span>
Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.
</span>
T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}

Winner: our team, then Blue, then Red, then Yellow

<span>
</span>

3 0
3 years ago
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