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NeTakaya
3 years ago
11

Just tell me the steps, not the answer please. This diagram shows the aerial view of a playground. What is the area of the playg

round to the nearest square yard? Use the value = 3.14.

Mathematics
1 answer:
Oxana [17]3 years ago
5 0

Area of the circle = π * (35 yd)^2

Let <em>A</em> be the area of the sector subtended by a central angle measuring 80º. Then

<em>A</em> / (π * (35 yd)^2) = 80º / 360º  ==>  <em>A</em> = 2450π/9 yd^2 ≈ 854.78 yd^2

Subtract from <em>A</em> the area of the triangle, whose base has length 45 yd and with height 25 yd:

<em>A</em> - 1/2 * (45 yd) * (25 yd)  ≈ 292.28 yd^2

This is the area of the missing circular segment.

Then the area of the playground is equal to the area of the circle minus this area,

π * (35 yd)^2 - 292.28 yd^2 ≈ 3554 yd^2

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Answer:

81/15

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14/3 would become 70/15 and 11/5 would become 33/15 and 70+33 is 103, so 103/5. 103/15 - 22/15 = 81/15.

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In the diagram below, is the perpendicular bisector of JK. Which of the following statements must be true?
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3 years ago
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2 years ago
The mean consumption of bottled water by a person in the United States is 28.5 gallons per year. You believe that a person consu
Over [174]

Answer:

t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707    

p_v =P(t_{99}

If we compare the p value with a significance level for example \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

Step-by-step explanation:

Data given and notation    

\bar X=27.8 represent the mean for the account balances of a credit company

s=4.1 represent the population standard deviation for the sample    

n=1000 sample size    

\mu_o =28.5 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to determine if the mean for the person consume is more than 28.5 gallons, the system of hypothesis would be:    

Null hypothesis:\mu \geq 28.5    

Alternative hypothesis:\mu < 28.5    

We don't know the population deviation, so for this case we can use the t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707    

Calculate the P-value    

First we need to calculate the degrees of freedom given by:

df=n-1=100-1=99

Since is a one-side lower test the p value would be:    

p_v =P(t_{99}

In Excel we can use the following formula to find the p value "=T.DIST(-1.707,99)"  

Conclusion    

If we compare the p value with a significance level for example \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

5 0
3 years ago
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