According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.
By using this theorem we can set up the system of equations as follows:
x=y+1 ...(1)
2x+3= 3y + 3 ..(2)
By using equation (1) next step is to plug in y+1 for x in equation (2). So,
2 ( y + 1) + 3 = 3y + 3
2y + 2 + 3 = 3y + 3 By using distribution property.
2y + 5 = 3y + 3
2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.
2y = 3y - 2
2y - 3y = -2 Subtract 3y from each sides.
-y = -2
So, y=2
Next step is to plug in y=2 in equation (1) to get the value of x. Hence,
x= 2+1
=3
So, x=3 and y=2 make these triangles congruent.
So, the correct choice is 3. x = 3, y = 2.
Answer:
57
Step-by-step explanation:
uhm I can't help with that... sorry
2(-n - 3) -7(5+2n)
-2n - 6 - 35 - 14n
-16n - 41
B. -16 - 41
Answer:
Step-by-step explanation:
ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:
We have:
Substitute:
<em>cross multiply</em>
Use the Pythagorean theorem:
Substitute:
