Question

If a single die is rolled four ​times, what is the probability it lands on 4 on the first comma second and third nothingnothing​rolls, but not on any of the other​ rolls?

Answer 1

Answer:

probability comes out to be $\dfrac{5}{1296}$

Step-by-step explanation:

when the dice is singly rolled

chances of getting 4  (Y)is $\dfrac{1}{6}$

and,

chance of not getting 4 (N) is $\dfrac{5}{6}$

probability of getting 4 on first, second and third time and not on the forth time is

P( Y, Y, Y, N ) = $\dfrac{1}{6} \times \dfrac{1}{6} \times \dfrac{1}{6} \times \dfrac{5}{6}$

                      = $\dfrac{5}{1296}$

so the probability comes out to be $\dfrac{5}{1296}$