a.
This is the geometric sequence: a1 = 1.5 m = 150
cm, r = 0.74
The formula now is an = a1 x r ^ n-1
Just substitute a1 = 150 cm and r = 0.74
an = 150 x (0.74) ^ n – 1
b.
The second part is:
A6 = 150 x 0.74 ^ 6-1
= 150 x 0.74 ^5
= 150 x 0.221906624
= 33.28509936 cm
Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
Answer:
Option A. A and D
Step-by-step explanation:
This answer because they are both right triangles and are near the same size
Hope this helps!
