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3 years ago

Which represents all the values of x that make the rational expression 2x-4 over x-5 undefined?

Mathematics

2 answers:

julsineya [31]3 years ago

7 0

X=5 because the denominator can never equal zero or it will be undefined. and 5-5=0

quester [9]3 years ago

7 0

Answer:

x = 5

Step-by-step explanation:

The given rational expression is

$\dfrac{2x-4}{x-5}$

We need to find all the values of x that make the rational expression undefined.

The given expression is undefined if the value of denominator is equal to 0.

Equate the denominator equal to 0.

$x-5=0$

Add 5 on both sides.

$x-5+5=0+5$

$x=5$

It means the given expression is undefined for x=5. Therefore, the correct option is 2.

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

Simplify −0.5(6.5). (5 points) a −3.5 b −3.25 c 3.25 d 3.5

VMariaS [17]

Answer:

B. -3.25

Step-by-step explanation:

Multiplying by 0.5 is the same as divided by 2.

*Dont forget the negative.

-0.5(6.5)= 6.5/-2 = -3.25

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3 years ago

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vredina [299]

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Tema [17]

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