To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
Answer:
your answer is D
Step-by-step explanation:
hope this helps
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's
2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside
2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25
that is a circle center (2,-2.5) with radius √9.25
Answer:
20
Step-by-step explanation:
Substitute D=4 into 4 D.
4 x 5 = 20
Answer:
c = -4
Step-by-step explanation:
If f(x) = 2x^3 - x + c and f(2) = 10, plug in 2 for the x values in the function and make the function output 10.
10 = 2(2^3) - 2 + c Now, we only have to deal with one variable, that is c.
10 = 2(8) - 2 + c
10 = 16 - 2 + c
10 = 14 + c
-4 = c After simplifying, we get that c is -4.
To check this, plug in 2 for x, and -4 for c in the function. If the function produces 10 as the result, the halleluja!
f(2) = 2(2^3) - 2 - 4
f(2) = 2(8) - 2 - 4
f(2) = 16 - 2 - 4
f(2) = 10
