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3 years ago

Match the phrase!! Where does each one go to??

Mathematics

2 answers:

lora16 [44]3 years ago

5 0

Answer: uuf, hard

Step-by-step explanation: SORRY, DON'T KNOW

adell [148]3 years ago

4 0

Answer:

Image attached.

1 left 4 right

2 left 3 right

3 left 2 right

4 left 1 right

Step-by-step explanation:

When evaluated...

7 ÷ 1/4 = 7 * 4 = 28

2/3 ÷ 4/5 = 2/3 * 5/4 = 5/6

4/5 ÷ 3/2 = 4/5 * 2/3 = 8/15

1/4 ÷ 1/7 = 1/4 * 7 = 7/4

An image has been attached to better explain this.

You might be interested in

How many points of intersection are there between the graphs of the hyperbola and ellipse?

N76 [4]

The point of intersection is the point where two or more functions meet.

The graphs of the hyperbola and ellipse have 0 point of intersection

The given parameters are:

$\mathbf{3x^2 - 4y^2 + 4x - 8y + 4 = 0}$

$\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 0}$

To determine the points of intersection, we simply equate both equations.

So, we have:

$\mathbf{3x^2 + y^2 + 4x - 3y + 4 = 3x^2 - 4y^2 + 4x - 8y + 4 }$

Cancel out the common terms

$\mathbf{y^2 - 3y = - 4y^2 - 8y }$

Collect like terms

$\mathbf{y^2 +4y^2= 3y - 8y }$

$\mathbf{5y^2= - 5y }$

Divide through by 5

$\mathbf{y^2= - y}$

Divide through by y

$\mathbf{y= -1}$

The system of equation does not give room to calculate the x-coordinate at the x-axis.

Hence, the graphs of the hyperbola and ellipse have 0 point of intersection

Read more about points of intersection at:

brainly.com/question/13373561

4 0

3 years ago

PLEASE HURRY WILL MARK BRAINLIEST!!!

LekaFEV [45]

Answer:

-7y+8x

Step-by-step explanation:

-2y-x-5y+9x

3 0

3 years ago

Read 2 more answers

Mike has two containers, One container is a rectangular prism with width 2 cm, length 4cm, and height 10cm. The other is a cylin

saul85 [17]

so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.

we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.

$\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{prism's volume}}{(4)(2)(h)}~~+~~\stackrel{\textit{cylinder's volume}}{(\pi )(1)^2(h)}~~=~~80 \\\\\\ 8h+\pi h=80\implies h(8+\pi )=80\implies h=\cfrac{80}{8+\pi }\implies h\approx 7.180301999$