Y=x^2-5
y=2x-5
y+5=2x
x=(y+5)/2
y=((y+5)/2)^2-5
y=(y^2+10y+25)/4-5
4y=y^2+10y+25-20
0=y^2+6y+5
0=(y+5)(y+1)
y= -5 or -1
y=2x-5 (y= -5 doesn't work for this one so use -1)
-1=2x-5
2x=4
x=2
Using these answers, you can choose answer D with reasonable certainty.
Answer:
m = 3
n = 14
p = 2
Step-by-step explanation:
Given:
We need to find the values of m, n, p
Solution:
We will first solve the L.H.S
L.H.S = 
Now we will first make the denominator common by taking L.C.M
Now the denominator is common hence we will subtract the numerators.
L.H.S 
Now Comparing the the value of L.H.S with R.H.S we can say that;
m = 3
n = 14
p = 2
The slope is m = 0 and the line goes through the point (x,y) = (2,3). So x = 2 pairs up with y = 3.
Plug m = 0, x = 2, y = 3 into the equation below. Then solve for b
y = mx+b
3 = 0*2+b
3 = 0+b
3 = b
b = 3
So if m = 0 and b = 3, then
y = mx+b
y = 0*x+3
y = 0+3
y = 3
is the equation of this line. This line is completely horizontal going through points like (0,3), (1,3), (2,3), etc. Every point on this line has a y coordinate of 3. The x coordinate can be any number you want.
Answer: Choice C) y = 3
