E is 5 more than d. fis 7 less than d. a) Write an expression for e in terms of d.
2 answers:
You might be interested in
Answer:
The average score of 6 tests is 19.
Step-by-step explanation:
Given that the average score of 5 tests is 18. So first, we have to find the total number of scores for 5 tests :
We have found out that the total scores for 5 tests is 90. So we have to find the average of 6 scores :
Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)