To find the x value of the max of
f(x)=ax^2+bx+c
when a is negative (if a is positive, we find the minimum)
we do
-b/2a is the x value
to find the y value, we just sub that x value back into the function
so
R(x)=-0.2x^2+60x+0
-b/2a=-60/(2*0.2)=-60/-0.4=150
x value is 150
make 150 units
sub back to find revenue
R(150)=-0.2(150)^2+60(150)
R(150)=-0.2(22500)+9000
R(150)=-4500+9000
R(150)=4500
max revenue is achieved when 150 units are produced yeilding $4500 in revenue
Answer:
5
Step-by-step explanation:
Answer: A: 63
Step-by-step explanation:
How i remember doing this, is that I put the numbers in ascending order (as in lowest to highest) and once I'm done i look for the middle number, so you have 22,44,63,63,71,80,92 it helps me by looking at the numbers on the right and left, or put them in groups, so we have 22,44,63 (that's one group) then we have 71,80,92 (that's another group) so the only number we have left is 63 the middle number, that's your answer :]
