C because you don’t put a force of which you choose and the force wouldn’t be strong enough
It had better be a vector, otherwise there's be no excuse for calling it a "velocity". It would just be the muzzle speed.
Answer:
The required angular speed the neutron star is 10992.32 rad/s
Explanation:
Given the data in the question;
mass of the sun M = 1.99 × 10³⁰ kg
Mass of the neutron star
M = 2( M )
M = 2( 1.99 × 10³⁰ kg )
M = ( 3.98 × 10³⁰ kg )
Radius of neutron star R = 13.0 km = 13 × 10³ m
Now, let mass of a small object on the neutron star be m
angular speed be ω.
During rotational motion, the gravitational force on the object supplies the necessary centripetal force.
GmM = / R² = mRω²
ω² = GM = / R³
ω = √(GM = / R³)
we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²
we substitute
ω = √( ( 6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)
ω = √( 2.65466 × 10²⁰ / 2.197 × 10¹²
ω = √ 120831133.3636777
ω = 10992.32 rad/s
Therefore, The required angular speed the neutron star is 10992.32 rad/s
Answer:
NO
Explanation:
The angular position of a diffraction null is given by
Asinθ=m λ=m c/f
Given that A is the slit width,
and m is an integer.
The wavelength of the second null satisfies
λ= A sinθ₁/2
of which if there were distinct third null it will satisfy
sinθ₂=3λ/A= 3* sin 45/2
λ=(3*0.7071)/2
λ=2.121/2
λ=1.060
Of which 1.060 is greater than 1
The correct answer is "wavelength".
In fact, the wavelength of a wave corresponds to the distance between two consecutive same-shape points of the wave: for instance, the distance between two consecutive crests, or the distance between two consecutive throughs.
For the wave in this problem, t<span>he distance between two consecutive crests is 2.5 meters, therefore the wavelength of the wave is 2.5 m.</span>