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Stolb23 [73]
3 years ago
15

In the macroscopic world, you know that you can hear but cannot see around corners. Under what conditions does light bend around

corners (i.e. diffract) ? Explain why sound diffracts easily around a classroom door. 5. Suppose you added to the single slit an identical slit a distance d=0.25mm away from the first. Draw the resulting interference pattern you might expect on the same screen. What happens when we increase the distance between slits ? What happens in the limit that d becomes arbitrarily large?
Physics
1 answer:
omeli [17]3 years ago
6 0

Answer:

a much larger slit, the phenomenon of Sound diffraction that slits for light.

this is a series of equally spaced lines giving a diffraction envelope

Explanation:

The diffraction phenomenon is described by the expression

    d sin θ = m λ

Where d is the distance of the slit, m the order of diffraction that is an integer and λ the wavelength.

 

For train the diffraction phenomenon, the d / Lam ratio is decisive if this relation of the gap separation in much greater than the wavelength does not reduce the diffraction phenomenon but the phenomena of geometric optics.

The wavelength range for visible light is 4 10⁻⁷ m to 7 10⁻⁷ m. The wavelength range for sound is 17 m to 1.7 10⁻² m. Therefore, with a much larger slit, the phenomenon of Sound diffraction that slits for light.

When we add a second slit we have the diffraction of each one separated by the distance between them, when the integrals are made we arrive at the result of the interference phenomenon, a this is a series of equally spaced lines giving a diffraction envelope

When I separate the distance between the two slits a lot, the time comes when we see two individual diffraction patterns

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The Moon orbits the Earth in an approximately circular path. The position of the moon as a function of time is given by: x(t) =
Aleks [24]

Answer: Average Velocity = - 643.42 i + 512.66 j m/s

Magnitude = 822.7 m/s

Direction = 141.45°

Explanation:

r = 3.84 x 10^8 m

w = 2.46 x 10^-6 rad/s

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at t = 0

x(0) = r

y(0) = 0

at t = 8.45 days

= 8.45 x 24 x 3600 s =730080 sec

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xf = r cos(w t) = - 0.2233r

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= - 643.42 i + 512.66 j m/s

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8 0
3 years ago
Read 2 more answers
If a = 2.0 cm, b = 5.0 cm, and i = 20 a, what is the magnitude of the magnetic field at the point p?
attashe74 [19]

If a = 2.0 cm, b = 5.0 cm, and i = 20 a,  6.0 μt is the magnitude of the magnetic field at the point p, So the correct option is (a).

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

B_{1} = μ_{0} i \frac{\pi }{6} / 4\pi (a+b)

B_{2} = μ_{0} i \frac{\pi }{6} / 4\pi b

As, B_{1} is moving down and B_{2} is moving up so,

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B_{2} - B_{1} = μ_{0} i 24 / (\frac{1}{b} - \frac{1}{a+b} )

B_{2} - B_{1} = \frac{4\pi *10^{-7}*20 }{24} (\frac{1}{0.05} -\frac{1}{0.02})

B_{2} - B_{1} = 5.98×10^{-6} T ≈ 6μT

Therefore,  6.0 μt is the magnitude of the magnetic field .

Learn more about  magnetic field here;

brainly.com/question/23096032

#SPJ4

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